这个问题可能已经回答,但是经过大量时间搜索,网络和网络没有找到合适的答案。
我连续3个循环如下:
w = my_text0.get(1.0, END).split()
data = []
# get & set the matching dict keys and values
for i in w:
if i in [*dictionary]:
word = i.title()
my_text.insert(END, word)
my_text.insert(END, ", " + dictionary[i] + "\n")
keys_len = len(word)
print("keys_len", keys_len)
data.append(keys_len)
print("data", data)
# print("keys_len", keys_len)
# get text widget lines count
txtwidg_lnescnt = int(my_text.index("end-1c").split(".")[0])
for j in range(0, len(data)):
k_l = data[j]
print("k_l", k_l)
print("k_l out", k_l)
# get index start and end for tag_add method
for k in range(1, txtwidg_lnescnt):
lne_idx = k
str_idx = f"{lne_idx}.0"
end_idx = f"{lne_idx}.{k_l}"
print("end_idx", end_idx)
my_text.tag_add("start", str_idx, end_idx)
my_text.tag_config(
"start",
background="red",
foreground="black",
font=bdfont,
)
我需要在3rd loop
中处理2nd loop
的k_l
值。
但是目前只处理2nd loop
的最后一个值(9)
。
这是我得到的输出:
keys_len 5
keys_len 6
keys_len 9
data [5, 6, 9]
k_l 5
k_l 6
k_l 9
k_l out 9
end_idx 1.9
end_idx 2.9
end_idx 3.9
我需要它:
keys_len 5
keys_len 6
keys_len 9
data [5, 6, 9]
k_l 5
k_l 6
k_l 9
k_l out 9
end_idx 1.5
end_idx 2.6
end_idx 3.9
我熟悉append to an empty list method
来存储循环中的所有值。
但是我不能在这里重复,因为它已经在1st loop
中完成了。
我还尝试使用return from a separate function method
,但它像嵌套环一样输出,这不是我需要的:
def mykeyslengths():
# get the user's entered words
w = my_text0.get(1.0, END).split()
data = []
# get & set the matching dict keys and values
for i in w:
word = i
keys_len = len(word)
print("keys_lenzz", keys_len)
data.append(keys_len)
for j in range(0, len(data)):
k_l = data[j]
print("k_l", k_l)
return k_l
def generate():
# Clear The text
my_text.delete(1.0, END)
# get the user's entered words
w = my_text0.get(1.0, END).split()
# data = []
# get & set the matching dict keys and values
for i in w:
if i in [*dictionary]:
word = i.title()
my_text.insert(END, word)
my_text.insert(END, ", " + dictionary[i] + "\n")
# keys_len = len(word)
# print("keys_len", keys_len)
# data.append(keys_len)
# print("data", data)
# print("keys_len", keys_len)
# get text widget lines count
txtwidg_lnescnt = int(my_text.index("end-1c").split(".")[0])
# for j in range(0, len(data)):
# k_l = data[j]
# print("k_l", k_l)
# print("k_l out", k_l)
# get index start and end for tag_add method
for k in range(1, txtwidg_lnescnt):
lne_idx = k
str_idx = f"{lne_idx}.0"
end_idx = f"{lne_idx}.{mykeyslengths()}"
print("end_idx", end_idx)
my_text.tag_add("start", str_idx, end_idx)
my_text.tag_config(
"start",
background="red",
foreground="black",
font=bdfont,
)
这样的输出:
keys_lenzz 5
keys_lenzz 6
keys_lenzz 9
k_l 5
k_l 6
k_l 9
end_idx 1.9
keys_lenzz 5
keys_lenzz 6
keys_lenzz 9
k_l 5
k_l 6
k_l 9
end_idx 2.9
keys_lenzz 5
keys_lenzz 6
keys_lenzz 9
k_l 5
k_l 6
k_l 9
end_idx 3.9
如果从示例中不清楚,我需要5, 6, 9
到bold
的长度,并修改由end_idx
变量值以tkinter
tag_add
END INDEX属性确定的相应子线的长度的backgrounds
和foregrounds
。
我目前遇到的问题是,所有3个子字节(字典键)都是(9)相同的长度,而它们的长度都应相同(5、6、9)。
分析解答
这应该有效:
w = my_text0.get(1.0, END).split()
data = []
# get & set the matching dict keys and values
for i in w:
if i in [*dictionary]:
word = i.title()
my_text.insert(END, word)
my_text.insert(END, ", " + dictionary[i] + "\n")
keys_len = len(word)
print("keys_len", keys_len)
data.append(keys_len)
print("data", data)
# print("keys_len", keys_len)
# get text widget lines count
txtwidg_lnescnt = int(my_text.index("end-1c").split(".")[0])
for j in range(0, len(data)):
k_l = data[j]
print("k_l", k_l)
print("k_l out", k_l)
# get index start and end for tag_add method
for k in range(1, txtwidg_lnescnt):
lne_idx = k
str_idx = f"{lne_idx}.0"
end_idx = f"{lne_idx}.{data[k-1]}"
print("end_idx", end_idx)
my_text.tag_add("start", str_idx, end_idx)
my_text.tag_config(
"start",
background="red",
foreground="black",
font=bdfont,
)