如何在不使用列表推导的情况下从python 3的嵌套列表中删除多个项目？有时Indexerror会如何处理？

split_list =[["a","b","c"],["SUB","d","e",],["f","Billing"]]
rem_word = ['SUB', 'Billing', 'Independent', 'DR']
for sub_list in split_list:
  for sub_itm in sub_list:
    if sub_itm not in rem_word:
        print(sub_itm)

输出如下：

 a
 b
 c
 d
 e
 f

预期产量：

split_list =[["a","b","c"],["d","e",],["f"]]
分析解答

您可以使用始终使用list-comprehension。在单独的列表中获取所有要删除的单词，然后尝试以下操作：

>>> split_list =[["a","b","c"],["SUB","d","e",],["f","Billing"]]
>>> rem_word = ['SUB', 'Billing', 'Independent', 'DR']
>>> output = [[sub_itm for sub_itm in sub_list if sub_itm not in rem_word] for sub_list in split_list]
[['a', 'b', 'c'], ['d', 'e'], ['f']]

如果要在不理解列表的情况下执行此操作，则需要声明一个空列表以附加每个新的sub-list，还需要声明一个空的sub-list以附加所有新的sub-items。检查一下：

output2 = []
for sub_list in split_list:
    new_sub_list = []
    for sub_itm in sub_list:
        if sub_itm not in rem_word:
            new_sub_list.append(sub_itm)
    output2.append(new_sub_list)

输出相同：

[['a', 'b', 'c'], ['d', 'e'], ['f']]