如何在URI（例如：Android和Corp）中对$search变量的GET请求进行编码，以获取（Android％2Band％2BCorp）而不是（Android + and + Corp）？

Form_

 <form action="search.php" method="GET">
  <input type="text" name="search" placeholder="Search.." id="myInput" onkeyup="filterFunction()">
  <input value="1" name="chank" id="one" type="radio" checked />
  <label for="one" class="switch__label">1</label>
  <input value="2" name="chank" id="two" type="radio" />
  <label for="two" class="switch__label">2</label>
  </form>

search.php_

$search=$_GET['search'];
$channel=$_GET['chank'];
$page=$_GET['page'];
include "conf/info.php";
$title = 'Result | '.$search;
include "header.php";
include "api/api_search.php";

GET_ api.php

$cs = curl_init();
curl_setopt($cs, CURLOPT_URL, "".$home."".$vapi."/search/".$chank."?api_key=".$key."&language=".$lang."&query=".$search."&page=".$page."");
curl_setopt($cs, CURLOPT_RETURNTRANSFER, TRUE);
curl_setopt($cs, CURLOPT_HEADER, FALSE);
curl_setopt($cs, CURLOPT_HTTPHEADER, array("Accept: application/json"));
$response = curl_exec($cs);
curl_close($cs);
$search = json_decode($response);

但是我在地址栏中仍然得到'+'而不是真正的'％2B'

分析解答

好像curl正在将您的字符串从_GET（带有+）编码为％2b。您可以在构建curlopt URL之前使用urldecode（）获取“原始”代码：

$s = 'some+cool+string';
echo $s . PHP_EOL; // some+cool+string
echo urlencode($s) . PHP_EOL; // some%2Bcool%2Bstring
echo urldecode($s) . PHP_EOL; // some cool string