排序！
我有2个表，一个表有负责人认购。第二个表有product用户为每个订阅和他们的详细资料。我union无论是在mysql和查询表的工作100％的罚款，但是当我使用WHERE条件它返回所有的记录，而不筛选尝试筛选记录。
下面你可以找到我的查询！
SELECT subscription_products.subscription_id, users.id, users.full_name,
users.company, users.job, users.birthday, users.gender,
users.nric, users.passport_number, users.phone_country_code,
users.phone_number, users.handphone_country_code, users.handphone_number,
users.email, users.nationality, wallets.current_amount,
users.created_at, users.updated_at
FROM subscription_product_users
LEFT JOIN subscription_products
ON subscription_product_users.subscription_product_id = subscription_products.id
LEFT JOIN users
ON subscription_product_users.user_id = users.id
LEFT JOIN wallets
ON users.id = wallets.user_id
UNION
SELECT person_in_charge.subscription_id, person_in_charge.user_id,
users.full_name,
users.company, users.job, users.birthday, users.gender,
users.nric, users.passport_number, users.phone_country_code,
users.phone_number, users.handphone_country_code,
users.handphone_number, users.email, users.nationality, wallets.current_amount,
users.created_at, users.updated_at
FROM person_in_charge
LEFT JOIN users
ON person_in_charge.user_id = users.id
LEFT JOIN wallets
ON person_in_charge.user_id = wallets.user_id
where subscription_id = '1378'
有人可以帮助我吗？
分析解答
尝试把它包起来，它的工作
SELECT * FROM
(SELECT subscription_products.subscription_id, users.id, users.full_name,
users.company, users.job, users.birthday, users.gender,
users.nric, users.passport_number, users.phone_country_code,
users.phone_number, users.handphone_country_code, users.handphone_number,
users.email, users.nationality, wallets.current_amount,
users.created_at, users.updated_at
FROM subscription_product_users
LEFT JOIN subscription_products
ON subscription_product_users.subscription_product_id = subscription_products.id
LEFT JOIN users
ON subscription_product_users.user_id = users.id
LEFT JOIN wallets
ON users.id = wallets.user_id
UNION
SELECT person_in_charge.subscription_id, person_in_charge.user_id,
users.full_name,
users.company, users.job, users.birthday, users.gender,
users.nric, users.passport_number, users.phone_country_code,
users.phone_number, users.handphone_country_code,
users.handphone_number, users.email, users.nationality, wallets.current_amount,
users.created_at, users.updated_at
FROM person_in_charge
LEFT JOIN users
ON person_in_charge.user_id = users.id
LEFT JOIN wallets
ON person_in_charge.user_id = wallets.user_id)
as tempTable
where subscription_id = '1378'