我正在尝试使用guzzle来运行一些测试，以提示我的服务器提供JSON response，我将与我期望的response进行比较。问题是我无法使response与预期结果相匹配。我认为这主要是由于一些语法错误，但我不知道如何纠正这一点。
我已经尝试手动添加新行以输出应该是什么，但这只是将\n添加到string。
请参阅下面的控制台报告：
1) UserAgentTest::testGet
Failed asserting that two strings are equal.
--- Expected
+++ Actual
@@ @@
-'{"error":false,"user":{"id_customer":10,"name":"Nic","email":"[email protected]","password":"$2y$15$YN5A58syg5iIuHJ.5BR6j.ZpHGASqZID4l6k.M3xgH9jSPlojhzGK","x_coord":"-29.82188!-29.79044","y_coord":"31.02221!30.80688","address_name":"Home!Not home","address":"11 Rapson Road!11 everton road","country":null,"province":"KwaZulu-Natal!KwaZulu-Natal","city":"Durban!Durban","suburb":"Morningside!Kloof","postcode":"2639!3620","account":"sole","vat_num":"","reg_id":"","phone_number":"0836661065"}}'
+'
+
+{"error":false,"user":{"id_customer":10,"name":"Nic","email":"[email protected]","password":"$2y$15$YN5A58syg5iIuHJ.5BR6j.ZpHGASqZID4l6k.M3xgH9jSPlojhzGK","x_coord":"-29.82188!-29.79044","y_coord":"31.02221!30.80688","address_name":"Home!Not home","address":"11 Rapson Road!11 everton road","country":null,"province":"KwaZulu-Natal!KwaZulu-Natal","city":"Durban!Durban","suburb":"Morningside!Kloof","postcode":"2639!3620","account":"sole","vat_num":"","reg_id":"","phone_number":"0836661065"}}'
C:\wamp64\www\tests\UserAgentTest.php:32
FAILURES!
Tests: 2, Assertions: 3, Failures: 1.
分析解答
"actual" string中有2个领先的line-breaks：
+'
+
+{"error":false
您可以使用PHP的trim function从string的开头和结尾剥离空格。
self::assertEquals(trim($string1), trim($string2));
这将确保没有leading/trailing空白字符。
此外，您可能希望使用preg_replace去除所有换行符：
self::assertEquals(
trim(preg_replace('/\R+/', '', $string1)),
trim(preg_replace('/\R+/', '', $string2))
);