我想解析日期,但这发生了:
无法解析的日期:" 2019-08-06 08:26:17"(偏移0处)
try {
String string = " 2019-08-06 08:26:17";
DateFormat format = new SimpleDateFormat("MMM dd,yyyy hh:mm a");
Date date = format.parse(string);
Log.d("datesssss", date.toString());
} catch (ParseException e) {
Log.d("datessssError", e.toString());
}
分析解答
试试这个:
SimpleDateFormat df2 = new SimpleDateFormat("yyyy-mm-dd hh:mm:ss");
SimpleDateFormat df3 = new SimpleDateFormat("MMM dd,yyyy hh:mm a");
String eDate ="2019-08-06 08:26:17";
Date eDDte;
try {
eDDte = df2.parse(eDate);
System.out.println("Date: " + df3.format(eDDte));
} catch(ParseException e){
e.printStackTrace();
}